Help me out NT Vol. Math

[jpioneer]

First of all, this not homework, I'm just practicing and can't solve this.

50*(1-e^(-10k))=20

I need help solving the k

Thank you.

 

[infamousod]

50*(1-e^(-10k))=20

(1-e^(-10k))= .4

e^(-10k)= .6

now you have to use log, and I don't have my scientific on me

 

[infamousod]

nevermind it's ln

ln(.6) = -10k

- .51 = -10k

k = .051


haven't done this in 5 years

 

[jpioneer]

Thank you man, I was trying to do it the same way but put the ln there too early so it just made it messy and confused me.

 

[romedadude]

Bagatrix

That helped me pass my math class this past semester

 

[jpioneer]

Originally Posted by romedadude

Bagatrix

That helped me pass my math class this past semester

I have to check this out

 

[thecalculator]

Originally Posted by infamousod

damn, you beat me to it.

 

[jpioneer]

Need a little help again... Part of the same exercise but forget everything said ealier.



y= distance travelled
t= time
k= constant

m=meter(unit)
s=second(unit)

y=50m*(1-e^(-kt/s))

Calculate the the speed by derivating the speed as the function of t


I'm desperate... I know the answer put don't know how to get there.

(answer is about 2.554m/s*e^(-kt/s))

 

[notoriouspat]

Originally Posted by JPioneer

First of all, this not homework, I'm just practicing and can't solve this.

we talkin about PRACTICE?

 

[jpioneer]

Originally Posted by notoriousPAT

Originally Posted by JPioneer

First of all, this not homework, I'm just practicing and can't solve this.

we talkin about PRACTICE?

Already tried to solve for like 2 hours. Best believe it's not my first option to ask here.