Math help vol. it was so long ago

23mcpizzle23

23mcpizzle23

10,884
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Joined
Mar 25, 2006
my brother wants me to help with his math im stuck on these 2, and he doesn't have the book
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11: Simplify, leaving as little as possibleinside absolute-value sign: | -6y² |

a. 6y²
b. -6y²
c. 6 | y² |
d. -6 | y² |

12: Simplify, leaving as little as possibleinside absolute-value sign: | -6y |

a. 6y
b. -6y
c. 6 | y |
d. -6 | y |
 
cant find it on google thanks for your help...


yea i know it may be easy forgot how to do this crap havent had a math class in years, just trying to help my bro...
 
Explain how it's A for 12.
I understand that we can not assume Y is positive. Let's say Y for instance was -2 than A would give you -12 which is wrong, the answer should be 12.

For C you get 6*|-2| = 12 the correct answer.

I could be wrong though.
 
wow yeah a and c thats ridiculous ive take through calc 3 and diffeq and i cant even get those right....
 
Originally Posted by BroboCop

Yall looking way to hard into this.


Absolute value of |-6y| = 6y
Click to expand...


No sir, it's not that simple. You are not sure whether the variable is positive or negative, so you cannot simply drop the absolute value bars. Y mustremain in them because it can be a negative number, so taking them out would give you a negative number as an answer which is not possible with absolute value.
 
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it's all so negative man...the man's most positive, positive tiv...is a negative...is a mega-negative!

a and c fool
 
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