TRIGONOMETRY??

Joined
Jul 7, 2009
Messages
2,031
Reaction score
162
NT idk if this is how to go about this but threads get off the first page in general so fast...

I have a trig take home test about identities and i have no idea about the principles and need some serious help. there are only 4 more problems left so itwont be too time consuming...
anyone willing to help it would be greatly appreciated!
thanks in advance, hopefully.
 
^
laugh.gif
at the reply & sig combo.
 
I'm a outer space balla, put you up on astronomy,
Mathematically, with a pistol, I do trigonometry.
 
hahaha i did laugh, inside my head. there are 6 problems i have to answer 4 of them...these are the problems:
2cotX=csc(squared)XsinX
2+2cot(squared)X=2cotXsecXcscX
cotX/2sinX=1+cosX
2sinX-cscX=sinX-(cotX/secX)
1=cot(squared)X=2cotXcsc2X
sinXcosX=(cosX-cos(cubed)X/sinX)
 
Originally Posted by cbrooks3

hahaha i did laugh, inside my head. there are 6 problems i have to answer 4 of them...these are the problems:
2cotX=csc(squared)XsinX
2+2cot(squared)X=2cotXsecXcscX
cotX/2sinX=1+cosX
2sinX-cscX=sinX-(cotX/secX)
1=cot(squared)X=2cotXcsc2X
sinXcosX=(cosX-cos(cubed)X/sinX)
Google is your friend.
 
google didnt help me much...and i know NT isnt really the place to ask but i thought maybe there was a smart dude here feeling generous.
 
cotΘdamn you are stupid
roll.gif
roll.gif


Edit: I would really want to help you bro, but my teacher just started teaching it this quarter. Just learned Sine, cosine, tangent, cosecant, secant, andcotangent today. Although I had to teach myself some trig for vectors in Physics...
smh.gif
 
That stuff isn't terribly hard, but it is time consuming. Just manipulate the identities. I.E. sin^2x + cos^2x = 1, divide both sides by cos^2x to getsin^2x/cos^2x + 1 = 1/cos^2x, that's the same as tan^2x + 1 = sec^2x.
 
Originally Posted by bkdan1

That stuff isn't terribly hard, but it is time consuming. Just manipulate the identities. I.E. sin^2x + cos^2x = 1, divide both sides by cos^2x to get sin^2x/cos^2x + 1 = 1/cos^2x, that's the same as tan^2x + 1 = sec^2x.

my teacher says that when we do it we are only supposed to work on one side at a time so it isnt like solving an algebraec problem...thanks for all of thefeedback though. much more than i expected
laugh.gif
 
Back
Top Bottom