NT, I need help in math again...

burymeag

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And yes, I tried reading through my textbook, tried going on youtube, tried googling, tried reading my notes but im just NOT getting it.

Like right now, i learn how to find the slope for one problem, then the next problem is COMPLETELY something different but theyre asking me to find the slope for it. I just sit here and rage 
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I think I have some mental illness with numbers because i cant even get this basic math down (Im taking Finite Math in college aka basic math)

When it comes to any liberal arts class (history, poli sci, english, etc) i can get it like flying colors. But with numbers I feel like im honestly mentally challenged 
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I got like... a 560 on my SAT math and im pretty sure thats above avg. but i just dont know whats wrong with me....

Im a Sophomore in college btw and my major is history education (tryna be a history teacher)
 
Bruh...

Are you really struggling with slope?

:lol

Aren't there like 3 different formulas to figure that **** out?
 
What was the question?
Find the sloper for: y-3=5(x+4)

The answer is 5/4 (Yes, i looked at the back of my book smh) but im trying to learn how to get that.

Do I put it in standard form first? (which i also had trouble doing... smh)

but when i tried i get stuck here:

y-3=5(x+4)

add 3 to get y by itself right?

so y=3+5(x+4).....?

i honestly have no idea wtf to do. I know in y=mx + b "m" is the slope..
wait+period > lame threads
Cool. Go cry somewhere else.
 
Bruh...

Are you really struggling with slope?

laugh.gif


Aren't there like 3 different formulas to figure that **** out?
Again, i honestly think i have a mental disorder. I already have adhd so maybe that plays a factor? idk even know. glad its funny tho
 
My bad. Why don't you youtube a few walk-throughs?

I'm laughing because you're on NT asking for help instead of helping yourself.
 
My bad. Why don't you youtube a few walk-throughs?

I'm laughing because you're on NT asking for help instead of helping yourself.
uhh did you even read what I wrote? I tried everything I could to help myself. Google, my notes, youtube, kahn academy.com or whatever its called..

its like once i get a problem down, the next problem is something completely different to me 
 
 
Like someone said earlier, put it in Slope-Intercept form (y=mx + b). You are correct, "m" is the slope.

So how do you go from y-3=5(x+4) to the slope intercept form? We have to isolate the y variable.

Don't confuse yourself by moving things around UNTIL you get rid of all parenthesis.

So we can say the original equation is the same as:

y-3=5x+20

Now, we can move the 3 over.

y=5x+23

That is slope intercept form. The slope is 5 (mx, where m = 5). Your book should say 5, that is the correct answer.

Let me know if that makes sense.
the book says the answer is 5/4 though.. and when you moved the 3 over, doesnt it go to the furthest left?

so it'll look like y=3+5x=20....?
 
Bruh...

Are you really struggling with slope?

:lol

Aren't there like 3 different formulas to figure that **** out?
OP failed the written permit test twice


 

Like someone said earlier, put it in Slope-Intercept form (y=mx + b). You are correct, "m" is the slope.

So how do you go from y-3=5(x+4) to the slope intercept form? We have to isolate the y variable.

Don't confuse yourself by moving things around UNTIL you get rid of all parenthesis.

So we can say the original equation is the same as:

y-3=5x+20

Now, we can move the 3 over.

y=5x+23

That is slope intercept form. The slope is 5 (mx, where m = 5). Your book should say 5, that is the correct answer.





Let me know if that makes sense.

the book says the answer is 5/4 though.. and when you moved the 3 over, doesnt it go to the furthest left?

so it'll look like y=3+5x=20....?

When it goes over, it would be at the furtherest right:

y= 5(x+4) + 3
y=5x+20+3
y=5x+23
 
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The book is incorrect. I checked my answer twice and used Wolfram Alpha to confirm.

You added an extra equals sign, you can't do that. When I move the 3 over, it crosses over the equals sign and can go anywhere on that side of the equation. I chose to keep it on the right side for clarity. It became y = 5x + 20 + 3.

If you have trouble with this, go to your TA. It is hard to explain math through text on the internet. Your university must offer some sort of tutoring.
oh i meant y= 3 + 5x + 20. so i cant do that either? it always goes to the furthest right?

and are you 1000000000% sure the book is wrong? 
laugh.gif
 
 
 

The book is incorrect. I checked my answer twice and used Wolfram Alpha to confirm.

You added an extra equals sign, you can't do that. When I move the 3 over, it crosses over the equals sign and can go anywhere on that side of the equation. I chose to keep it on the right side for clarity. It became y = 5x + 20 + 3.


If you have trouble with this, go to your TA. It is hard to explain math through text on the internet. Your university must offer some sort of tutoring.


oh i meant y= 3 + 5x + 20. so i cant do that either? it always goes to the furthest right?


and are you 1000000000% sure the book is wrong? :lol  

you can do it this way...

just remember to follow the order of operations.

And I also got 5 as the slope.
 
The answer is y=5x+23, with 5 being the slope.

You distribute the 5 to the factors in the parentheses before you carry over the 3 to leave y stand alone.
 
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Is all the info given in the problem in your posts? Looks like they are using rise/run. You can plot that line and will likely get the 5/4 answer using the intercepts. It's been ages since I've done this stuff tho so i'm not sure.
 
 
why is this homework help thread permitted. 
I actually think it'd be a good idea to make an official homework help thread instead of having several threads of one question each. Now that classes are starting up again I think NTers could really help each other out.
 
'Homework help' threads are against the rules though
 
'Homework help' threads are against the rules though
Any legitimacy as to why they're excluded?

I mean... If there's a real question, and the teacher allows outside help, what's the problem?

99% are on Google anyways.
 
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'Homework help' threads are against the rules though

I don't understand that.

It's not like he's just asking for answers and nothing else. He actually wants to learn how to solve it himself.
 
Post your questions, ill solve them step by step, take a pic and post it here. Engineering major ftw, I know you won't encounter anhing harder than the stuff I went through (no offense intended)
 
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